Question 3 • Pre-Algebra B
The two samples contain 4 brown trout altogether (3 + 1) out of 50 fish total (15 + 3 + 9 + 11 + 1 + 11). Brown trout make up 4/50, or 8%, of the sampled fish. Applying that proportion to the estimated population of 1,000 gives 0.08 × 1,000 = 80 brown trout, so the answer is 80.
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