Question 7 • OK-Algebra II A
First multiply the monomial factors: (a²)(2a³) = 2a⁵. Then distribute 2a⁵ across each term: 2a⁵(a²) = 2a⁷, 2a⁵(−8a) = −16a⁶, and 2a⁵(9) = 18a⁵. The product is 2a⁷ − 16a⁶ + 18a⁵, which is choice A.
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