Question 3 • Mathematics III
Divide by the second fraction by multiplying by its reciprocal: \(\frac{A-3}{7}\times\frac{21}{3-A}\). Since \(3-A=-(A-3)\), the factors involving \(A-3\) cancel with a negative sign, and \(21/7=3\), giving \(-3\) (for \(A\ne3\), so the original divisor is not zero). The correct choice is negative 3.
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