AnswersACHS-Fundamental Algebra A-CREstimating and Finding Decimal Products

Multiplying Fractions Answers

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Which could be used to evaluate the expression ?

Question illustration
A
(Negative 6) (4) + (negative 6) (two-thirds)
Option A
B
(Negative 6) (4) times (negative 6) (two-thirds)
Option B
C
(Negative 6 + 4) + (Negative 6 + two-thirds)
Option C
D
(Negative 6 + 4) times (negative 6 + two-thirds)
Option D
5

Nico and Lorena used different methods to determine the product of three fractions. Nico’s MethodLorena’s MethodWhose solution is correct and why?

Question illustration
A
Nico is correct because he knew that .
Option A
B
Nico is correct because he knew that .
Option B
C
Lorena is correct because she knew that
Option C
D
Lorena is correct because she knew that
Option D
6

Which expression could be used to determine the product of –4 and ?

Question illustration
A
(negative 4) (3) times (negative 4) (one-fourth)
Option A
B
(negative 4) (3) + (negative 4) (one-fourth)
Option B
C
(3) (negative 4) times (3) (one-fourth)
Option C
D
(3) (negative 4) + (3) (one-fourth)
Option D
8

Which shows how the distributive property can be used to evaluate ?

Question illustration
A
56 + StartFraction 28 over 5 EndFraction = 56 + 5 and three-fifths = 61 and three-fifths
Option A
B
56 times StartFraction 28 over 5 EndFraction = StartFraction 1568 over 5 EndFraction = 313 and three-fifths
Option B
C
15 + (StartFraction 35 over 5 EndFraction + four-fifths) = 15 + StartFraction 39 over 5 EndFraction = StartFraction 75 over 5 EndFraction + StartFraction 39 over 5 EndFraction = StartFraction 114 over 5 EndFraction = 22 and four-fifths
Option C
D
15 times (StartFraction 35 over 5 EndFraction + four-fifths) = 15 times StartFraction 39 over 5 EndFraction = StartFraction 15 over 1 EndFraction times StartFraction 39 over 5 EndFraction = StartFraction 585 over 5 EndFraction = 117
Option D
10

Calvin evaluated using the steps below.Step 1: Step 2: Step 3: Step 4: Which describes Calvin’s error?

Question illustration
A
In step 1, he incorrectly broke up .
Option A
B
In step 2, he distributed the instead of the 5.
Option B
C
In step 2, he confused the multiplication and addition signs.
D
In step 3, he computed the addition and multiplication incorrectly.
11

The result of which expression will best estimate the actual product of ?

Question illustration
A
(Negative 1) (one-fourth) (Negative 1) (negative 1)
Option A
B
(Negative 1) (one-half) (Negative 1) (1)
Option B
C
(Negative StartFraction 4 over 2 EndFraction) (Three-halves) (Negative two-fifths) (Five-halves)
Option C
D
(Negative three-fourths) (Negative three-fourths) (Negative one-fifth) (One-half)
Option D
12

Ivan and Polina have each drawn a conclusion about multiplying negative fractions. Ivan: The product of an even number of negative fractions is always positive. Polina: The product of an odd number of negative fractions is always negative. Whose conclusion is correct?

A
Ivan only
B
Polina only
C
both Ivan and Polina
D
neither Ivan or Polina
13

Which is the best estimate of ?

Question illustration
A
–42
B
–28
C
28
D
42
14

Which is the best estimate of ?

Question illustration
A
–18
B
–9
C
9
D
18
15

Calvin evaluated using the steps below.Step 1: Step 2: Step 3: Step 4: Which describes Calvin’s error?

Question illustration
A
In step 1, he incorrectly broke up .
Option A
B
In step 2, he distributed the instead of the 5.
Option B
C
In step 2, he confused the multiplication and addition signs.
D
In step 3, he computed the addition and multiplication incorrectly.
16

Vassil rounded to the nearest half to estimate the product of and . How do the estimated and actual products compare?(Hint: use 18 for the denominator when comparing.)

Question illustration
A
The actual product is about greater than the estimate.
Option A
B
The actual product is about less than the estimate.
Option B
C
The actual product is about greater than the estimate.
Option C
D
The actual product is about less than the estimate.
Option D
17

Adante begins to evaluate the expression using the steps below.Which could be his next step?

Question illustration
A
(3) (5) + (one-third) (5) + (3) (one-fourth) + (one-third) (one-fourth)
Option A
B
(3) (5) + (3) (one-third) + (3) (one-fourth) + (3) (one-third)
Option B
C
(3 and one-third) (3 and one-third) + (5) (one-fourth)
Option C
D
(3 and one-third + 3 and one-third) times (5 + one-fourth)
Option D
18

Which could be used to evaluate the expression ?

Question illustration
A
(Negative 6) (4) + (negative 6) (two-thirds)
Option A
B
(Negative 6) (4) times (negative 6) (two-thirds)
Option B
C
(Negative 6 + 4) + (Negative 6 + two-thirds)
Option C
D
(Negative 6 + 4) times (negative 6 + two-thirds)
Option D
19

A leaky pool loses inches of water each day. Jermaine and Mildred are asked to determine the change in the amount of water in the pool over 5 days. Jermaine’s SolutionMildred’s SolutionWhich describes the reasoning used to determine whose solution is correct?

Question illustration
A
Jermaine is correct because equals
Option A
B
Jermaine is correct because he distributed 5 correctly.
C
Mildred is correct because she multiplied 5 by –2 but not by .
Option C
D
Mildred is correct because she distributed 5 correctly.

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