Question 6 • (AG Q3) Math 8: 25-26 (JTurner)
Let a be the number of algebra problems and g the number of geometry problems. The total number gives a + g = 27, and the time gives 2a + 5g = 90. Substituting a = 27 − g into the time equation gives 54 + 3g = 90, so g = 12 and a = 15. Rob had 15 algebra problems, choice D.
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