Question 79061 • Adv. Algebra II S2 Original
Distribute each term in 3a + 5 across 2a² + 4a − 2. This gives 6a³ + 12a² − 6a + 10a² + 20a − 10. Combine like terms to get 6a³ + 22a² + 14a − 10, which is choice A.
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