28
QuizMultiple Choice

N/A — Exam

Question 28 • Statistics

The agent tests ratio of cap h sub 0 to mu sub 1 minus mu sub 2 is equal to 0 , ratio of cap h sub A to mu sub 1 minus mu sub 2 is less than 0 , where mu sub 1 is equal to the true mean selling price of all comparable empty homes and mu sub 2 is equal to the true mean selling price of all comparable staged homes. The conditions for inference are met. What are the values of the test statistic and cap p -value for a t - test about a difference in means? Use the t -table.

Answer
A
t is equal to the fraction with numerator 150 comma 000 minus 175 comma 000 and denominator square root of the fraction with numerator 22 comma 000 squared and denominator 5 plus the fraction with numerator 35 comma 000 squared and denominator 5 end root . The cap p -value is between 0 point 1 0 and 0 point 1 5 .
B
t is equal to the fraction with numerator 150 comma 000 minus 175 comma 000 and denominator square root of the fraction with numerator 22 comma 000 squared and denominator 5 plus the fraction with numerator 35 comma 000 squared and denominator 5 end root . The cap p -value is between 0 point 2 0 and 0 point 3 0 .
C
t is equal to the fraction with numerator 150 comma 000 minus 175 comma 000 and denominator square root of the fraction with numerator 22 comma 000 squared and denominator 5 minus the fraction with numerator 35 comma 000 squared and denominator 5 end root . The cap p -value is between 0 point 1 0 and 0 point 1 5 .
D
t is equal to the fraction with numerator 150 comma 000 minus 175 comma 000 and denominator square root of the fraction with numerator 22 comma 000 squared and denominator 5 minus the fraction with numerator 35 comma 000 squared and denominator 5 end root . The cap p -value is between 0 point 2 0 and 0 point 3 0 .

Explanation

For two independent samples, the standard error of the difference in sample means uses the sum of the two sample-variance terms. Thus, t = (150,000 − 175,000) / √[(22,000²/5) + (35,000²/5)] ≈ −1.35. Because the alternative is that μ₁ − μ₂ < 0, this is a left-tailed test; using the t-table with the approximate degrees of freedom gives a P-value between 0.10 and 0.15. Choice A gives both the correct statistic and P-value range.

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