Question 28 • Statistics
For two independent samples, the standard error of the difference in sample means uses the sum of the two sample-variance terms. Thus, t = (150,000 − 175,000) / √[(22,000²/5) + (35,000²/5)] ≈ −1.35. Because the alternative is that μ₁ − μ₂ < 0, this is a left-tailed test; using the t-table with the approximate degrees of freedom gives a P-value between 0.10 and 0.15. Choice A gives both the correct statistic and P-value range.
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