To do so, she selects a random sample of 100 orders from the large number of orders that were filled and determines who filled the order. She finds that Erica filled 56 orders, Jen filled 18 , Heather filled 14 , and Tonya filled 12 The chi-square test statistic for goodness of fit is chi squared is equal to 11 point 2 0 and the cap p -value is between 0 point 0 1 and 0 point 0 2 Do the data provide convincing evidence that the distribution of the number of orders filled is not adhering to the agreed-upon percentages? Use A is equal to 0 point 0 5
Answer
A
No. Because the cap p -value is less than the significance level there is convincing evidence that the distribution of the number of orders filled is adhering to the agreed-upon percentages.
B
Yes. Because the cap p -value is less than the significance level there is convincing evidence that the distribution of the number of orders filled is not adhering to the agreed-upon percentages.
C
No. Because the cap p -value is less than the significance level there is not convincing evidence that the distribution of the number of orders filled is not adhering to the agreed-upon percentages.
D
Yes. Because the cap p -value is less than the significance level there is convincing evidence that the distribution of the number of orders filled is adhering to the agreed-upon percentages.
Explanation
The null hypothesis is that the order distribution follows the agreed-upon percentages. The p-value is between 0.01 and 0.02, which is below the significance level of 0.05, so we reject that hypothesis. The data provide convincing evidence that the distribution is not adhering to the agreed-upon percentages, as stated in choice B.
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