The relationship between voltage, cap e , current, cap i , and resistance, cap z , is given by the equation cap e is equal to cap i cap z If a circuit has a current cap i is equal to 3 plus 2 i and a resistance cap z is equal to 2 minus i , what is the voltage of the circuit?
Use the relationship E = IZ and multiply (3 + 2i)(2 − i). This gives 6 − 3i + 4i − 2i²; since i² = −1, the result is 8 + i. The voltage is 8 + i, choice C.
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