The height h , in feet, of a projectile t seconds after launch is modeled by the equation h is equal to 32 t minus 16 t squared How long after launch does the projectile return to the ground?

The projectile is on the ground when its height is 0, so set 32t − 16t² = 0. Factoring gives 16t(2 − t) = 0, which has solutions t = 0 and t = 2. Since t = 0 is the launch time, it returns to the ground after 2 seconds, choice D.

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