Question 85 • Algebra II
Let b be the number of basic phones and u the number of upgraded phones. The store’s purchase cost gives 10b + 50u = 400, or b + 5u = 40; its sales give 60b + 200u = 1,800, or 3b + 10u = 90. Substituting b = 40 − 5u into the sales equation gives 3(40 − 5u) + 10u = 90, so u = 6. The store sold 6 upgraded phones.
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