An object is launched at an initial velocity of 19 point 6 meters per second from an initial height of 24 point 5 meters. Which equation can be used to find the number of seconds it takes the object to hit the ground?

For vertical motion in meters, the height after t seconds is h(t) = -4.9t² + v₀t + h₀. Substituting the initial velocity 19.6 m/s and initial height 24.5 m gives h(t) = -4.9t² + 19.6t + 24.5. The object hits the ground when its height is 0, so choice A is the equation to solve.

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