Aluminum has a frequency threshold of 9 point 8 4 6 times 10 to the 14th power Hz Which best explains what will happen when light with a frequency below the frequency threshold strikes aluminum?

In the photoelectric effect, a photon must have at least the threshold frequency to give an electron enough energy to escape the metal. Light below aluminum’s threshold frequency does not meet that requirement, regardless of how intense the light is. Therefore, no electrons will be ejected; the correct choice is “No electrons will be ejected.”

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