Consider the rate law below. cap r is equal to k cap A cap b squared What effect does doubling the concentration of each reactant have on the rate?

The rate law is r = k[A][B]². Doubling [A] multiplies the rate by 2, while doubling [B] multiplies it by 2² = 4 because its exponent is 2. Together, these changes multiply the rate by 2 × 4 = 8, so the rate increases to eight times its original value.

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