AnswersAlgebra II - MA3111 A-CRUnit Test

Negative Exponents Answers

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1
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What is the product of ?

Question illustration
A
StartFraction 6 Over y Superscript 8 Baseline EndFraction
Option A
B
StartFraction 1 Over 6 y Superscript 6 Baseline EndFraction
Option B
C
StartFraction 6 Over y Superscript 16 Baseline EndFraction
Option C
D
StartFraction 1 Over 6 y Superscript 16 Baseline EndFraction
Option D
2
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What is the quotient of ?

Question illustration
A
StartFraction 1 Over 343 EndFraction
Option A
B
One-seventh
Option B
C
7
D
49
3

Which expression is equivalent to ?

Question illustration
A
-(16)4
B
164
C
RootIndex 4 StartRoot one-sixteenth EndRoot
Option C
D
Negative (one-sixteenth) Superscript negative 4
Option D
4

Which expression is equivalent to 9–2?

A
–81
B
–18
C
StartFraction 1 Over 81 EndFraction
Option C
D
StartFraction 1 Over 18 EndFraction
Option D
5

Which expression is equivalent to 6–3?

A
–63
B
36
C
RootIndex 3 StartRoot 6 EndRoot
Option C
D
(One-sixth) cubed
Option D
6

Which expression is equivalent to ?

Question illustration
A
StartFraction 1 Over 2 Superscript 15 Baseline EndFraction
Option A
B
StartFraction 1 Over 2 Superscript 8 Baseline EndFraction
Option B
C
28
D
215
7

Which expression is equivalent to ?

Question illustration
A
–81
B
–12
C
StartFraction 1 Over 81 EndFraction
Option C
D
One-twelfth
Option D
8

Which expression is equivalent to 5y–3?

A
StartFraction 1 Over 125 y cubed EndFraction
Option A
B
StartFraction 1 Over 5 y cubed EndFraction
Option B
C
StartFraction 5 Over y cubed EndFraction
Option C
D
StartFraction 125 Over y cubed EndFraction
Option D
9

Which expression is equivalent to (10x)–3?

A
StartFraction 10 Over x cubed EndFraction
Option A
B
StartFraction 1000 Over x cubed EndFraction
Option B
C
StartFraction 1 Over 1000 x cubed EndFraction
Option C
D
StartFraction 1 Over 10 x cubed EndFraction
Option D
10

Describe how to simplify the expression .

Question illustration
A
Divide the bases and then add the exponents.
B
Keep the base the same and then add the exponents.
C
Multiply the bases and then subtract the exponents.
D
Keep the base the same and then subtract the exponents.
11

Anja simplified the expression to . What mistake did Anja make?

Question illustration
A
She divided the exponents instead of subtracting them.
B
She divided the coefficients instead of subtracting them.
C
She subtracted the coefficients instead of dividing them.
D
She subtracted the exponents instead of dividing them.
12

Which expression is equivalent to (3a)–2?

A
StartFraction 1 Over 9 a squared EndFraction
Option A
B
StartFraction 1 Over 3 a squared EndFraction
Option B
C
StartFraction 3 Over a squared EndFraction
Option C
D
StartFraction 9 Over a squared EndFraction
Option D
13

What is the quotient of ?

Question illustration
A
StartFraction 1 Over 256 EndFraction
Option A
B
One-half
Option B
C
1
D
256
14

Which expression is equivalent to ?

Question illustration
A
y5
B
y6
C
125y3
D
125y5
15

What is the quotient of ?

Question illustration
A
StartFraction x Superscript 9 Baseline Over 32 EndFraction
Option A
B
4x9
C
Negative StartFraction 12 Over x squared EndFraction
Option C
D
–2x9
16

Describe how can be simplified.

Question illustration
A
Multiply the bases and add the exponents. Then find the reciprocal and change the sign of the exponent.
B
Keep the same base and add the exponents. Then multiply by –1.
C
Keep the base and multiply the exponents. Then multiply by –1.
D
Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

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