How long does current 2 have to run to deliver the same amount of charge as current 1 ? Current 1 of 8 point 4 cap A runs for 240 seconds and then stops. Current 2 is 10 point 5 cap A

The charge delivered is current multiplied by time, so set the charges equal: I₁t₁ = I₂t₂. Thus, t₂ = (8.4 ÷ 10.5) × 240 s = 192 s. Current 2 must run for 192 seconds, which is choice A.

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