Question 10 • Algebra III A
Distribute each term: (3 – 5i)(–2 + 4i) = –6 + 12i + 10i – 20i². Since i² = –1, the last term is +20, giving a real part of –6 + 20 = 14 and an imaginary part of 12i + 10i = 22i. The product is 14 + 22i, choice B.
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