What is oxidized and what is reduced in this reaction?N2H4(l) + 2H2O2(l) → N2(g) + 4H2O(g)

In N₂H₄, hydrogen is +1, so each nitrogen is −2; in N₂, nitrogen is 0. Nitrogen’s oxidation state increases, so N is oxidized. Oxygen changes from −1 in H₂O₂ to −2 in H₂O, so O is reduced. The correct choice is C, “N is oxidized and O is reduced.”

AI-written and checked against the verified answer.