Consider this equilibrium reaction. Ni raised to the 2 plus power times A q plus Sn times s long left right arrow Ni times s plus Sn raised to the 2 plus power times A q The forward reaction is non-spontaneous. What does this indicate about the relative strengths of the reducing and oxidizing agents on each side of the equation?

If the forward reaction is non-spontaneous, the reverse reaction is spontaneous. A spontaneous reaction proceeds from the stronger reducing and oxidizing agents toward weaker ones, so in the reverse direction the stronger agents are Ni(s), the reducing agent, and Sn²⁺(aq), the oxidizing agent. These are on the right side of the equation as written, so the stronger agents are on the right.

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