Question 10 • Chemistry
Carbon contributes 10 × 12.01 = 120.10 g/mol. The compound’s molar mass is 120.10 + (14 × 1.008) + (2 × 14.01) = 162.23 g/mol. Thus, the percent by mass of carbon is (120.10 ÷ 162.23) × 100 ≈ 74.02%, so the correct choice is 74.02 percent.
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