What is the empirical formula for a compound if a sample contains 1.0 g of S and 1.5 g of O?

Convert each mass to moles: 1.0 g S ÷ 32.1 g/mol ≈ 0.031 mol S, and 1.5 g O ÷ 16.0 g/mol ≈ 0.094 mol O. Dividing both amounts by the smaller value gives an approximate ratio of 1 S to 3 O, so the empirical formula is SO₃, choice B.

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