Question 13 • Algebra III A
Multiply each term: (3 − 5i)(−2 + 4i) = −6 + 12i + 10i − 20i². Since i² = −1, −20i² = 20, so the real terms give −6 + 20 = 14 and the imaginary terms give 12i + 10i = 22i. The product is 14 + 22i, choice B.
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