The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?

Compare y = 3(x − 7) with point-slope form y − y₁ = m(x − x₁). The slope is 3, the x-coordinate is 7, and because there is no value subtracted from y, y₁ is 0. Harold used the point (7, 0), choice C.

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