What is the argument of z is equal to 1 over 16 minus the fraction with numerator square root of 3 and denominator 16 i ?

The real part is 1/16 and the imaginary part is −√3/16, so z lies in the fourth quadrant. Since |imaginary part ÷ real part| = √3, the reference angle is π/3; therefore the argument is −π/3, choice negative π over 3.

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