Question 4 • Precalculus
For z = -2√3 - 6i, the modulus is √((-2√3)² + (-6)²) = √48 = 4√3. Both parts are negative, so the point is in quadrant III; its reference angle is π/3, giving θ = 4π/3. Thus the polar form is 4√3(cos(4π/3) + i sin(4π/3)), which is choice C.
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