The real roots for the equation x to the 4th power minus x cubed plus 10 x squared minus 16 x minus 96 is equal to 0 are negative 2 and 3 What are the nonreal solutions?

For a monic quartic, the product of all four roots equals the constant term, −96. The two known roots have product (−2)(3) = −6, so the product of the two nonreal roots must be (−96)/(−6) = 16. Since the coefficients are real, the nonreal roots are conjugates; their product is 16 and their sum is 0, so they are −4i and 4i. The correct choice is C, negative 4i and 4i.

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