A polynomial function has a root of negative 6 with multiplicity 1 , a root of negative 2 with multiplicity 3 , a root of 0 with multiplicity 2 , and a root of 4 with multiplicity 3 If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?

For x greater than 4, the polynomial is positive because its leading coefficient is positive. Crossing the root 4, which has odd multiplicity 3, changes the sign, so the polynomial is negative on (0, 4). The root 0 has even multiplicity 2, so the sign stays negative on (-2, 0); crossing -2, which has odd multiplicity 3, changes it to positive on (-6, -2). Therefore, the graph is positive on (-6, -2), as choice B states.

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