AnswersTX-Precalculus A-CRPolynomial Inequalities

Polynomial Inequalities Answers

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5

The graph of f(x) = (0.2)(x4 + x3 – 12x2) is shown.

Question illustration
A
(–4, 0) U (0, 3)
B
[–4, 0) U (0, 3]
C
(–ꝏ, –4) U (3, ꝏ)
D
(–ꝏ, –4] U [3, ꝏ)
6

What is the solution to (x – 5)(x + 2)(x – 7) < 0?

A
A number line going from negative 8 to 8. Open circles are at negative 2, 5, and 7. The line is shaded to the left of negative 2 and between 5 and 7.
Option A
B
A number line going from negative 8 to 8. Open circles are at negative 2, 5, and 7. The line is shaded between negative 2 and 5 and to the right of 7.
Option B
C
A number line going from negative 8 to 8. Closed circles are at negative 2, 5, and 7. The line is shaded to the left of negative 2 and between 5 and 7.
Option C
D
Option
Option D
8

What is the solution to x 4 – 12x 2 + 10 > 0?

A
(–0.95, 0.95)
B
(–3.33, 3.33)
C
(–3.33, –0.95) U (0.95, 3.33)
D
(–ꝏ, –3.33) U (–0.95, 0.95) U (3.33, ꝏ)
10

What is the solution to (x – 5)(2x + 1)(x – 7) > 0?

A
(–0.5, 5) U (7, ꝏ)
B
(–ꝏ, –0.5) U (5, 7)
C
(–0.5, 5] U [7, ꝏ)
D
(–ꝏ, –0.5] U [5, 7]
11

What is the solution to x 3 + x 2 ≤ 10x – 8?

A
{–4, 1, 2}
B
(–ꝏ, –4]
C
(–ꝏ, –4) U [1, 2]
D
(–ꝏ, –4] U [1, 2]
12

The cube of a number is less than five times the square of the number. For what set of numbers is this true?

A
(–ꝏ, 5)
B
(5, ꝏ)
C
(–ꝏ, 0) U (0, 5)
D
(–ꝏ, 5) U (5, ꝏ)
14

Consider the graph of f(x) = 2x 3 – 3x 2 – 14x.

Question illustration
A
–2 < x < 0 or 3.5 < x < ꝏ
B
–2 < x < 0 or 3.5 ≤ x ≤ ꝏ
C
–2 ≤ x ≤ 0 or 3.5 ≤ x ≤ ꝏ
D
–2 ≤ x ≤ 0 or 3.5 ≤ x < ꝏ
15

What is the solution to (x + 2)(x – 3)2 > 0?

A
A number line going from negative 4 to 4. The entire line is shaded with arrows going left and right.
Option A
B
A number line going from negative 4 to 4. An open circle is at negative 2. The line is shaded to the right of negative 2.
Option B
C
A number line going from negative 4 to 4. Open circles are at negative 2 and 3. The line is shaded between negative 2 and 3.
Option C
D
A number line going from negative 4 to 4. Open circles are at negative 2 and 3. The line is shaded to the right of negative 2.
Option D
16

What are the minimum and maximum values of x, for which x3 + x2 – 6x ≥ 0?

A
minimum = –3, maximum = 0
B
minimum = 0, maximum = 2
C
minimum = –3, no maximum
D
minimum = 2, no maximum
17

What is the solution to x6 – 6x 5 + 15x 4 – 20x 3 + 15x 2 – 6x + 1 ≥ 0?

A
x = 0
B
x = 1
C
all real numbers
D
all real numbers except zero

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