Population Proportion Answers

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The president of a bowling league wanted to estimate the average highest bowling score of all its 200 members. Instead of surveying all 200 members, she randomly selected 20 members and recorded their highest scores. She found the sample mean to be 237. What inference can she make based on the sample mean?

A
Every member in the league has bowled a 237 game.
B
The highest score ever bowled in the league was 237.
C
The average of the highest games bowled in the league was 237.
D
Out of the 200 members in the league, only 20 of them have ever bowled a 237 game.
2
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0.100.13✔ 0.31X 0.40

A
0.10
B
0.13
C
✔ 0.31
D
X 0.40
3

0.31X 0.6✔ 0.690.87

A
0.31
B
X 0.6
C
✔ 0.69
D
0.87
4

✔ 4.2X 5.17.68.1

A
✔ 4.2
B
X 5.1
C
7.6
D
8.1
126911

equal to✔ less thanX more than

A
equal to
B
✔ less than
C
X more than
126912

What is the minimum sample size, n, that he needs in order to meet these requirements? Complete the statements.

Answers:
The value of 3% represents the .:margin of error
In the formula n = (1 – ) • , the value of (1 – ) is .:0.59
When n is calculated, the result after rounding is .:1,033
126913

0.030.41✔ 0.59X 0.97

A
0.03
B
0.41
C
✔ 0.59
D
X 0.97
126914

✔ 1,0331,750X 2,1782,519

A
✔ 1,033
B
1,750
C
X 2,178
D
2,519
126915

Complete the statements to find the margin of error.

Answers:
The sample size in this problem is students.:800
Estimate the population proportion as .:0.31
(1 – ) = .:0.69
When the margin of error is calculated using the formula E = z* , to the nearest tenth of a percent, the result is %.:4.2
126916

Which confidence interval represents the estimated proportion of people willing to pay higher prices for gas?

A
between 50.5% and 68.1%
B
between 53.3% and 64.7%
C
between 54.2% and 63.8%
D
between 55.3% and 62.7%
126917

What is the minimum sample size, n, that he needs in order to meet these requirements? Complete the statements.

Answers:
The value of 3% represents the .:margin of error
In the formula n = (1 – ) • , the value of (1 – ) is .:0.59
When n is calculated, the result after rounding is .:1,033

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