Question 15 • Algebra II
Use a lower-tail z-test with H₀: μ = $72 and Hₐ: μ < $72. The test statistic is z = (67 − 72) ÷ (11 ÷ √40) ≈ −2.88. At the 1% significance level, the lower-tail critical value is −2.58; since −2.88 is smaller, reject H₀. The result supports the conclusion that the branch’s average receipt is below $72, matching choice C.
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