Question 13 • Mathematics II
Substitute y = 4x − 10 into y + 5x = x² + 10. This gives 4x − 10 + 5x = x² + 10, which rearranges to 0 = x² − 9x + 20, matching choice B. Factoring gives (x − 4)(x − 5) = 0, so x = 4 is one solution value, as stated in choice C.
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