A force of 60 cap n is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 cap n over m , and spring B has a spring constant of 5 cap n over m How do the lengths of the springs compare?

By Hooke’s law, the stretch is the force divided by the spring constant. Spring A stretches 60 ÷ 4 = 15 m, while spring B stretches 60 ÷ 5 = 12 m. Since the springs started at the same length, spring A is 15 − 12 = 3 m longer, so the correct choice is “Spring A is 3 m longer than spring B.”

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