What is the equation of the line in slope-intercept form that is perpendicular to the line y is equal to 3 fourths x minus 2 and passes through the point negative 12 comma 10 ?

The given line has slope 3/4, so a perpendicular line has slope −4/3, the negative reciprocal. Substitute the point (−12, 10) into y = −4/3x + b: 10 = 16 + b, which gives b = −6. Therefore, the equation is y = −4/3x − 6, choice B.

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