Question 14 • Geometry
There are 3 + 4 + 5 = 12 electives, so the number of ways to choose any 2 is 12 × 11 ÷ 2 = 66. For one computer elective and one art elective, there are 5 × 3 = 15 possible pairs. The probability is 15 ÷ 66 ≈ 0.227, so the answer is A, approximately 0.227.
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