If a compound has a molar mass of 180 g over mol and its empirical formula is cap c cap h sub 2 cap o , what is its molecular formula?

The empirical formula CH₂O has a mass of 12 + 2(1) + 16 = 30 g/mol. Divide the compound’s molar mass, 180 g/mol, by 30 g/mol to find the multiplier: 180 ÷ 30 = 6. Multiply each subscript in CH₂O by 6 to get C₆H₁₂O₆, choice C.

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