Question 2 • Algebra II
The first 200 multiples of 3 are 3, 6, 9, …, 600, so their sum is 3 times the sum of the integers from 1 to 200. Using 1 + 2 + … + 200 = 200 × 201 ÷ 2, the total is 3 × 200 × 201 ÷ 2 = 60,300, which is choice B.
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