Question 5 • Precalculus
For f(x) = 3|x − 4| + 1, the absolute value graph has its vertex at (4, 1), since x − 4 is zero when x = 4. The positive coefficient 3 means the V opens upward. One unit to either side of x = 4, the output is 3(1) + 1 = 4, so the graph passes through (3, 4) and (5, 4). Choice D matches these features.
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