Question 5 • Precalculus
Group the x-terms and y-terms, then complete the square: 9(x² − 6x) + 4(y² − 2y) = 59 becomes 9(x − 3)² + 4(y − 1)² = 144. Divide both sides by 144 to get (x − 3)²/16 + (y − 1)²/36 = 1. This is choice C, with both squared terms centered at (3, 1).
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