Question 10 • Mathematics I
For g(x) = (2/3)^x − 2, the base is between 0 and 1, so the exponential decreases as x increases. At x = 0, g(0) = 1 − 2 = −1, and as x gets larger, the graph approaches the horizontal asymptote y = −2. For sufficiently negative x, the function is positive; it then passes through the negative y-values and approaches −2, matching the graph described in choice D.
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