7
practice testMultiple Choice

Practice Test

Question 7 • Precalculus

What is the limit? limit x to 5 of open paren the fraction with numerator negative sine times open paren pi x over 3 close paren and denominator 3 close paren

Answer
A
the fraction with numerator square root of 3 and denominator 6
B
negative the fraction with numerator square root of 3 and denominator 6
C
negative the fraction with numerator 3 square root of 3 and denominator 2
D
the fraction with numerator 3 square root of 3 and denominator 2

Explanation

Since sine is continuous, substitute x = 5 into the expression: −sin(5π/3)/3. Because sin(5π/3) = −√3/2, the value is −(−√3/2)/3 = √3/6. The correct choice is the fraction with numerator √3 and denominator 6.

AI-written and checked against the verified answer.

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