Question 5 • Algebra: Concepts and Connections
Because the denominators are the same, subtract the numerators and keep the denominator: (3t² − 4t + 1) − (t² + 2t + 2). Distributing the negative gives 3t² − 4t + 1 − t² − 2t − 2 = 2t² − 6t − 1. Morgan’s numerator, 2t² − 2t + 3, suggests she changed the signs of the t² term but not the +2t and +2 terms. So she forgot to distribute the negative sign to two terms in the second expression.
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