Question 15 • Precalculus
The denominator has a repeated linear factor, (x + 1)², so the decomposition needs a constant numerator over each power: A/(x + 1) and B/(x + 1)². It also has the irreducible quadratic factor x² + 1 repeated three times, so each power needs a linear numerator: (Cx + D)/(x² + 1), (Ex + F)/(x² + 1)², and (Gx + H)/(x² + 1)³. This is the form shown in choice D.
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