The molar heat of fusion of gold is 12 point 5 5 0 kJ mol inverse At its melting point, how much mass of melted gold must solidify to release 235 point 0 kJ of energy? Use q is equal to n triangle cap h

Use q = nΔH_fus to find the amount of gold: n = 235.0 kJ ÷ 12.550 kJ/mol = 18.725 mol. Convert moles to mass using gold’s molar mass, 196.97 g/mol: 18.725 mol × 196.97 g/mol ≈ 3,688.3 g. Thus, 3,688.3 g of gold must solidify, which is choice B.

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