Given a pair of complex numbers, z sub 1 is equal to 5 and z sub 2 is equal to negative 6 i , let z sub 3 is equal to 3 i plus z sub 1 and z sub 4 is equal to z sub 2 minus 2 In which quadrant is z sub 3 minus z sub 4 located?

First, calculate z₃ = 5 + 3i and z₄ = −2 − 6i. Then z₃ − z₄ = (5 + 3i) − (−2 − 6i) = 7 + 9i. Both the real part and the imaginary part are positive, so the number is in quadrant I, choice D.

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