Question 10 • Precalculus
Use cos θ = (u · v) / (|u||v|). The dot product is (−3)(2) + (2)(1) = −4, and the vector lengths are √13 and √5, so cos θ = −4/√65. Taking the inverse cosine gives θ ≈ 119.7°, so the angle is 119.7° (choice C).
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