Law of Sines (Sec 8-3) — Unit test Answers
On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 6), point B is at (negative 1, 1), and point C is at (2, 2).
On a coordinate plane, quadrilateral J K L M with diagonals is shown. Point J is at (4, 5), point K is at (5, 1), point L is at (1, 2), and point M is at (1, 5).
On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, negative 2), and point K is at (negative 2, negative 3).
On a coordinate plane, rectangle W X Y Z is shown. Point W is at (negative 6, 6), point X is at (negative 4, 0), point Y is at (negative 7, negative 1), and point Z is at (negative 9, 5).
In the diagram, WZ=.
The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?
In the diagram, DG ∥ EF.
On a coordinate plane, square P Q R S is shown. Point P is at (4, 2), point Q is at (8, 5), point R is at (5, 9), and point S is at (1, 6).
On a coordinate plane, trapezoid J K L M is shown. Point J is at (negative 7, 4), point K is at (negative 4, 4), point L is at (negative 2, 3), and point M is at (negative 8, 3).
LMNP is a parallelogram.
On a coordinate plane, parallelogram K L M N shown. Point K is at (7, 7), point L is at (5, 3), point M is at (1, 1), and point N is at (3, 5).
The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?
On a coordinate plane, rhombus A B C D is shown. Point A is at (1, 1), point B is at (negative 2, negative 3), point C is at (negative 5, 1), and point D is at (negative 2, 5).
On a coordinate plane, rectangle W X Y Z is shown. Point W is at (negative 6, 6), point X is at (negative 4, 0), point Y is at (negative 7, negative 1), and point Z is at (negative 9, 5).
On a coordinate plane, quadrilateral J K L M with diagonals is shown. Point J is at (4, 5), point K is at (5, 1), point L is at (1, 2), and point M is at (1, 5).
In the diagram, DG ∥ EF.
On a coordinate plane, trapezoid J K L M is shown. Point J is at (negative 7, 4), point K is at (negative 4, 4), point L is at (negative 2, 3), and point M is at (negative 8, 3).
On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, negative 2), and point K is at (negative 2, negative 3).
LMNP is a parallelogram.
In the diagram, WZ=.
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