Question 1 • OK-Algebra I - Sem A-CR-35011A
Differentiate the function: y′ = 3x² + 2x − 6. Setting y′ = 0 gives x = (−1 ± √19)/3, approximately −1.8 and 1.1. The derivative changes from positive to negative at x ≈ −1.8, so this is the relative maximum; substituting it into the original function gives y ≈ 13.2. The relative maximum is (−1.8, 13.2), choice D.
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