A picture frame has a perimeter of 40 inches. Its length is 2 inches greater than one-half its width. Let w represent the width in inches of the picture frame, and let l represent the length in inches. Which system of equations can be used to find the dimensions of the picture frame?
Answer
A
the 2 by 1 column matrix row 1 l w is equal to 40 row 2 l is equal to 1 half w minus 2
B
the 2 by 1 column matrix row 1 2 l plus 2 w is equal to 40 row 2 l is equal to 2 plus 1 half w
C
the 2 by 1 column matrix row 1 2 l plus 2 w is equal to 40 row 2 l is equal to 1 half w minus 2
D
the 2 by 1 column matrix row 1 l w is equal to 40 row 2 l is equal to 2 plus 1 half w
Explanation
A rectangle’s perimeter is 2l + 2w, so the perimeter condition gives 2l + 2w = 40. The length is 2 inches greater than one-half the width, so l = 2 + ½w. These equations make choice B the correct system.
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