Question 6 • Algebra 2
For (0, 4), the first inequality requires y ≥ ½x² + 4. Substituting x = 0 gives 4 ≥ 4, which is true. The second requires y < √(x + 2) + 6; at x = 0, this is 4 < √2 + 6, also true. So (0, 4) is a solution.
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