Consider the equation 3 x cubed plus 14 x squared minus 14 x plus 60 is equal to 0 The real solution is negative 6 What are the nonreal solutions?

Since −6 is a root, divide the cubic by x + 6. The quotient is 3x² − 4x + 10, so solve 3x² − 4x + 10 = 0. Its discriminant is (−4)² − 4(3)(10) = −104, giving roots (4 ± 2i√26)/6 = (2 ± i√26)/3. These are choice C.

AI-written and checked against the verified answer.